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0=10+15x-4.9x^2
We move all terms to the left:
0-(10+15x-4.9x^2)=0
We add all the numbers together, and all the variables
-(10+15x-4.9x^2)=0
We get rid of parentheses
4.9x^2-15x-10=0
a = 4.9; b = -15; c = -10;
Δ = b2-4ac
Δ = -152-4·4.9·(-10)
Δ = 421
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{421}}{2*4.9}=\frac{15-\sqrt{421}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{421}}{2*4.9}=\frac{15+\sqrt{421}}{9.8} $
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